Sep 6, 2015 · 3 The definition of convolution is known as the integral of the product of two functions $$ (f*g) (t)\int_ {-\infty}^ {\infty} f (t -\tau)g (\tau)\,\mathrm d\tau$$ But what does the …

I am currently learning about the concept of convolution between two functions in my university course. The course notes are vague about what convolution is, so I was wondering if anyone …

Closed 9 years ago. Why do we define the convolution? Why is convolution useful? What is the purpose of the geometry of convolution of two functions in plane? Can we draw the …

I'm having a hard time understanding how the convolution integral works (for Laplace transforms of two functions multiplied together) and was hoping someone could clear the topic up or link …

Feb 27, 2024 · Definition of Convolution of functions of two variables Ask Question Asked 1 year, 10 months ago Modified 1 year, 10 months ago

Mar 14, 2015 · I doubt you can define convolution without some group structure on the manifold.

A shift-invariant linear operator T T is completely determined by its impulse response T(δ) = f T (δ) = f (where δ δ is the Dirac delta function). You can show that for any function g g, T(g) = f ∗ g T …

Jul 2, 2024 · Particularly the case where one of the functions is zonal and we can define convolution as $ (f*g) (x) = \int_M g (d (x,y))f (y)d\mu (y)$. I know there is a result like this for …

Oct 7, 2025 · Woronowicz's paper (Quantum deformation of Lorentz group) has some information about the convolution, but the actual definition is slightly different. Question 2.

Jun 20, 2018 · When I read the notes, a convolution is defined as: $(f*g)(x) =\\int_{-\\infty}^{+\\infty} f(\\tau)g(x-\\tau)\\rm{d}\\tau.$ What is the difference if we define a ...